Answer :
n; n + 1; n + 2 - three consecutive numbers
n + (n + 1) + (n + 2) = 144
3n + 3 = 144 |subtract 3 from both sides
3n = 141 |divide both sides by 3
n = 47 - the smallest of the three numbers
n + (n + 1) + (n + 2) = 144
3n + 3 = 144 |subtract 3 from both sides
3n = 141 |divide both sides by 3
n = 47 - the smallest of the three numbers
