Sisler554
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The launch site for trigon balloon co. is 250 ft above sea level. A hot air balloon is launched from the site and begins to rise at a rate of 110 ft/min. At the same time, another balloon 2200 ft above sea level begins to descend at a rate of 150 ft/min. A. How long will it be unit the balloons are at the same elevation? B. What will their elevation be then?



Answer :

SecretIndex
Set up the equations as equal: 
110x+250=-150x+2200
Add 150x to both sides:
260x+250=2200
Subtract 250 from both sides.
260x=1950
Divide both sides by 260.
x=7.5
A: They will meet at 7.5 minutes after launch
Plug in 7.5:
110(7.5)+250=11*75+250=825+250=1075
B: They will meet at 1075 feet

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