Answer :

[tex]\frac{1}{6}d+\frac{2}{3}=\frac{1}{4}(d-2) \\ \\ \frac{d}{6}^{(2}}+\frac{2}{3}^{(4}=\frac{d-2}{4}^{(3} \\ \\ 2d+8=3(d-2) \\ \\ 2d+8=3d-6 \\ \\ 2d-3d=-6-8 \\ \\ -d=-14 \\ \\ \boxed{d=14}[/tex]

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