if we call the area A, then [tex]A=7(x+2)=7x+14[/tex]
if we call the perimeter P, then [tex]P=7*2+2(x+2)=2x+18[/tex]
[tex]A>P[/tex]
[tex]7x+14>2x+18[/tex]
subtracting 14 gives [tex]7x>2x+4[/tex]
subtracting 2x gives [tex]5x>4[/tex]
dividing by 5 gives [tex]x>\frac{4}{5}[/tex]
or [tex]x>0.8[/tex]