Answer :

luana
[tex]\frac{1}{3}k+\frac{1}{2}=\frac{1}{4}k\ \ \ \ \ \ |\cdot12(to\ eliminate\ fractions)\\\\\frac{12}{3}k+\frac{12}{2}=\frac{12}{4}k\\\\4k+6=3k\\\\4k-3k=-6\\\\k=-6[/tex]

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