Answer :

mariamikayla
[tex]8(4p+1)=32p+8 \\\\ 32p+8=32+8 \\\\ 32p-32p=8-8 \\\\ \boxed{0=0}\\\\ Answer:p \ can \ take any \ value \ because \ every \ number \ would \ make \ the \ sentence \ true.[/tex]
AL2006
What is your question ?  Are you asking for the solution of the equation ?

The "solution" is the number that 'p' must be, in order to make the equation
a true statement.

When you eliminate the parentheses on the left side of the equation,
the left side becomes    32p + 8 .

Then the equation says    32p + 8  =  32p + 8 .

That's a true statement no matter what  'p'  is .

So any number and every number is a solution of the equation.

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