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the perimeter of a rectangle is 120 meters. If the length of the rectangle is 20 meters more than the width, what are the dimensions of the rectangle.



Answer :

L+l+L+l=120
L+l=60

L=l+20 so l+20+l=60, 2l=40, l=20, L=40

The dimensions are 20 wide, 40 long.
120= 2(w+20) + 2w
120= 2w+40+2w
120= 40+4w
80=4w
w=20
Length:
w+20
20+20
40
Width: 20
So the dimensions are:
Length is 40
Width is 20

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