" when striking, the pike, a predatory fish, can accelerate from rest to a speed of 4.0 m/s in 0.11 s."
The question is " how far does the pike move during his strike" for part b
Part A's answer is 36.36 repeating
In an uniform accelerated motion, the distance covered by the fish is given by: [tex]S= \frac{1}{2}at^2 [/tex] where a is the acceleration t is the time
The acceleration is equal to the increase in speed of the fish divided by the time taken: [tex]a= \frac{v_f-v_i}{t}= \frac{4 m/s-0m/s}{0.11 s}=36.4 m/s^2 [/tex] If substitute the acceleration into the first equation, we find the distance covered by the fish: [tex]S= \frac{1}{2}at^2= \frac{1}{2}(36.4 m/s^2)(0.11 s)^2=0.22 m [/tex]
