Answer :
y varies directly as x, and y =16 when x=8. Find y when x=16
y is double x
so when x=16
y=16x2 which equals 32
y is double x
so when x=16
y=16x2 which equals 32
For this case, since the variation is direct then we have a relation of the form:
[tex] y = kx
[/tex]
Where,
k: proportionality constant
To find k we substitute the following data:
y = 16 when x = 8
We have then:
[tex] 16 = k8
[/tex]
Clearing the value of k we have:
[tex] k = \frac{16}{8}
k = 2
[/tex]
Then, the equation is:
[tex] y = 2x
[/tex]
Substituting the value of x = 16 we have:
[tex] y = 2 (16)
y = 32
[/tex]
Answer:
The value of y for x = 16 is:
[tex] y = 32 [/tex]
