scazarockin
scazarockin scazarockin
  • 27-09-2014
  • Mathematics
Answered

The quadratic equation y=2x^2-px+6 has equal roots. Find the possible values of p.



Answer :

konrad509
konrad509 konrad509
  • 27-09-2014
[tex]\Delta=0\\ \Delta=(-p)^2-4\cdot2\cdot6=p^2-48\\ p^2-48=0\\ p^2=48\\ p=\sqrt{48} \vee p=-\sqrt{48}\\ p=4\sqrt3 \vee p=-4\sqrt3 [/tex]
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