Answer :
Three consecutive odd integers: n, n + 2, and n + 4
n + (n + 2) + (n + 4) = 165
3n + 6 = 165
3n + 6 - 6 = 165 - 6
3n = 159
3n / 3 = 159 / 3
n = 53
So the first number is n, or 53.
The second number is n + 2, or 55.
The third number is n + 4, or 57.
Hope this helps! :)
n + (n + 2) + (n + 4) = 165
3n + 6 = 165
3n + 6 - 6 = 165 - 6
3n = 159
3n / 3 = 159 / 3
n = 53
So the first number is n, or 53.
The second number is n + 2, or 55.
The third number is n + 4, or 57.
Hope this helps! :)
