Ramiro is 3/10 as tall as a flagpole. The flagpole is 5/9 as tall as a nearby tree. The tree is 32 2/5 feet tall. How tall is Ramiro?

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Gabriel24 Gabriel24 · Answer 1 · 2014-09-30T01:33:13-04:00

32 2/5 = 162/5
162/9 = 18
18 x 5 = 90
90/10 = 9
9 x 3 = 27.

That makes Ramiro 27/5 feet tall or you can also say he's 5 2/5 feet tall.

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calculista calculista · Answer 2 · 2018-07-31T07:48:59-04:00

Let

x---------> Ramiro's height

y--------> height of the flagpole

z-------> height of the tree

we know that

[tex] z=32\frac{2}{5} \\\\ z=(32*5+2)/5\\\\ z=\frac{162}{5} ft [/tex]

1) Find the height of the flagpole

[tex] y=\frac{5}{9} *\frac{162}{5} \\\\ y=\frac{162}{9} \\\\ y=18 ft [/tex]

2) Find the height of Ramiro

[tex] x=\frac{3}{10} *18\\ \\ x=\frac{54}{10} \\ \\ x=5.4 ft\\ \\ x=5\frac{2}{5} ft [/tex]

therefore

the answer is

The height of Ramiro is [tex] 5\frac{2}{5} ft [/tex]