If a number is divisible by 3, then the sum of its digits is divisible by 3 .
If ( h6h41 ) is divisible by 9, then both it and 1/3 of it must be divisible by 3.
If ( h6h41 ) is divisible by 3, then (2h + 6 + 4 + 1) = (2h + 11) is divisible by 3.
If 2h+11 = 12, h = 1/2
If 2h+11 = 15, h = 2
If 2h+11 = 18, h = 3-1/2
If 2h+11 = 21, h = 5
If 2h+11 = 24, h = 6-1/2
If 2h+11 = 27, h = 8
If 2h+11 = 30, h = 9-1/2
But 'h' is a digit, so it must be 2, 5, or 8 .
-- If h6h41 is 26,241 then 1/3 of it is 8,747 . . . not divisible by 3
-- If h6h41 is 56,541 then 1/3 of it is 18,847 . . . not divisible by 3
-- If h6h41 is 86,841 then 1/3 of it is 28,947 . . . divisible by 3
So ' h ' = 8, and the sum of the digits in h6h41 is 27 .
