Answer :
To check it we have to calculate.
LHS =[tex] \frac{16}{6} - \frac{2}{9} = \frac{48}{18}- \frac{4}{18} = \frac{44}{18} = 2 \frac{8}{18} [/tex]
And now we can check equality
RHS=[tex]2 \frac{4}{9} =2 \frac{8}{18} [/tex] = LHS
Its true.
LHS =[tex] \frac{16}{6} - \frac{2}{9} = \frac{48}{18}- \frac{4}{18} = \frac{44}{18} = 2 \frac{8}{18} [/tex]
And now we can check equality
RHS=[tex]2 \frac{4}{9} =2 \frac{8}{18} [/tex] = LHS
Its true.