Answer :
You don't say how many numbers you want to do that with.
If you want just two numbers, then they're +7.3107 and -12.3107 .
(Those are rounded, not exact.)
I took a quick look among the factors of 90, looking for sets of 3 numbers
that would do it, and I couldn't find any.
If you want just two numbers, then they're +7.3107 and -12.3107 .
(Those are rounded, not exact.)
I took a quick look among the factors of 90, looking for sets of 3 numbers
that would do it, and I couldn't find any.
let
x-------> the first number
y-------> the second number
we know that
[tex]x+y=-5 \\ x=-5-y[/tex] equation 1
[tex]x*y=-90[/tex] equation 2
substitute the equation 1 in equation 2
[tex][-5-y]*y=-90 \\ -5y- y^{2} =-90 \\ y^{2} +5y-90=0[/tex]
using a graphical tool to resolve the second order equation
see the attached figure
the numbers are
-12.311
7.311
x-------> the first number
y-------> the second number
we know that
[tex]x+y=-5 \\ x=-5-y[/tex] equation 1
[tex]x*y=-90[/tex] equation 2
substitute the equation 1 in equation 2
[tex][-5-y]*y=-90 \\ -5y- y^{2} =-90 \\ y^{2} +5y-90=0[/tex]
using a graphical tool to resolve the second order equation
see the attached figure
the numbers are
-12.311
7.311