Answer :

AL2006
You don't say how many numbers you want to do that with.

If you want just two numbers, then they're  +7.3107  and  -12.3107 .
(Those are rounded, not exact.)

I took a quick look among the factors of 90, looking for sets of 3 numbers
that would do it, and I couldn't find any.
let
x-------> the first number
y-------> the second number

we know that

[tex]x+y=-5 \\ x=-5-y[/tex] equation 1

[tex]x*y=-90[/tex] equation 2

substitute the equation 1 in equation 2

[tex][-5-y]*y=-90 \\ -5y- y^{2} =-90 \\ y^{2} +5y-90=0[/tex]

using a graphical tool to resolve the second order equation
see the attached figure
the numbers are
-12.311
7.311

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