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The length of a rectangle is 8 in. more than its width. The perimeter is 52 in.

What is the length of the rectangle?



Answer :

mariamikayla
[tex]L=w+8 \\\\ P=2L+2w \\ P=52in \\\\ 2(w+8)+2w=52 \\\\ 2w+16+2w=52 \\\\ 4w=52-16 \\\\ 4w=36 \\\\ \boxed{w=\frac{36}{4}=4in} \\\\ L=4+8 \\\\ \boxed{L=12in}[/tex]
It would be 17 for the length
And 9 for the width

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