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Determine the average atomic mass of helium, which has two isotopes having atomic masses 4.0026 amu and 3.0160 amu. The relative abundance of the two isotopes is 99.9999 percent and 0.0001 percent, respectively.



Answer :

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[tex]m_a=4.0026 \cdot 99.9999 \% + 3.0160 \cdot 0.0001 \%= \\ =4.0025959974+0.000003016= \\ =4,0025990134 \ [amu][/tex]

The average atomic mass of helium is 4,0025990134 amu.