Answer :
[tex]\angle \ a+ \angle \ b+ \angle \ c =180^0 \\\\ \angle a=\angle \ c=65^0 \\\\ 65^0+65^0+\angle \ b=180^0 \\\\ 130^0+\angle \ b=180^0 \\\\ \angle \ b=180^0-130^0 \\\\ \boxed{\angle \ b=50^0}[/tex]
The sum of the angles of a triangle is 180°.
x+ 65°+65°=180° /-130°
x=50°
⇒ the 3rd angle is [tex]50°[/tex]
