Answer :
what is the height of Fort Collins High School?
If found, use the formula, V=x/t-----------------(x=distance; t=time)
You have three known variables:
Acceleration - [tex]9.8m/s^2[/tex]
Time - [tex]1.85s[/tex]
Initial Velocity - [tex]0m/s[/tex]
For the first part of your question:
[tex]v = u + at v = (0)+(9.8)(1.1) v = 10.78 m/s
v=11 m/s (2 significant figures)[/tex]
For the second part of your question:
[tex]v=u+at v=(0)+(9.8)(1.85) v=18.13 m/s [/tex]
This still needs to be converted to m/h:
[tex]18.13m/s = 18.13\times 3600 metres/h=65628 metres/hour 65628 metres/hour = 65628\div1600 mi/h = 40.7925 mi/h = 41 mi/hr (2 significant figures) [/tex]
Acceleration - [tex]9.8m/s^2[/tex]
Time - [tex]1.85s[/tex]
Initial Velocity - [tex]0m/s[/tex]
For the first part of your question:
[tex]v = u + at v = (0)+(9.8)(1.1) v = 10.78 m/s
v=11 m/s (2 significant figures)[/tex]
For the second part of your question:
[tex]v=u+at v=(0)+(9.8)(1.85) v=18.13 m/s [/tex]
This still needs to be converted to m/h:
[tex]18.13m/s = 18.13\times 3600 metres/h=65628 metres/hour 65628 metres/hour = 65628\div1600 mi/h = 40.7925 mi/h = 41 mi/hr (2 significant figures) [/tex]