When Plutonium-239 undergoes alpha decay, it becomes A) curium-241 + an alpha particle B) uranium-235 + an alpha particle C) neptunium-237 + and alpha particle D) plutonium-237 + and alpha particle



Answer :

An alpha particle is composed of two protons and two electrons.

As a result, in alpha decay, the nucleus that decays loses two protons and two neutrons. So the mass number (239 in this case) decreases by 4.

239 - 4 = 235,

So the new nucleus must be B) Uranium-235, as it is the only one of the options that has an atomic mass of 235.

Answer:

The correct answer is option B.

Explanation:

Alpha decay: In this process, alpha particles is emitted when a heavier nuclei decays into lighter nuclei. The alpha particle released has a charge of +2 units.

The general alpha decay reaction is given as:

[tex]_Z^A\textrm{X}\rightarrow _{Z-2}^{A-4}\textrm{Y}+_2^4\alpha[/tex]

So, when Pu-239 undergoes alpha decay it gives Uranium-235 and alpha particle.

[tex]_{94}^{239}\textrm{Pu}\rightarrow _{92}^{235}\textrm{U}+_2^4\alpha[/tex]

Hence,the correct answer is option B.