Answer
Find out the three pairs for possible values for a and b .
To prove
As given
[tex]The\ product\ of\ two\ positive\ fractions\ a\ and\ b\ is\ \frac{15}{56} .[/tex]
i.e it is written in the form.
[tex]a\times b = \frac{15}{56}[/tex]
When
[tex]a = \frac{3}{2} , b = \frac{5}{28}[/tex]
Than
[tex]\frac{3\times 5}{2\times 28} = \frac{15}{56}[/tex]
When
[tex]a = \frac{3}{4} , b = \frac{5}{14}[/tex]
Than
[tex]\frac{3\times 5}{4\times 14} = \frac{15}{56}[/tex]
When
[tex]a = \frac{1}{2} , b = \frac{15}{28}[/tex]
Than
[tex]\frac{1\times 15}{2\times 28} = \frac{15}{56}[/tex]
Hence proved