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How do you solve the following compound inequality : 4b+18 is greater than or equal to -12b -14 less than or equal to 14 -5b



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luana
[tex]4b+18 \geq -12b-14 \leq 14-5b\\\\\ 4b+18 \geq -12b-14 \ \ and\ \ -12b-14 \leq 14-5b\\\\ 16b \geq -32\ \ \ and\ \ \ -7b \leq 28\\\\ b \geq -2\ \ \ and\ \ \ b \geq 4\\\\ Solution\ is\ b\in[4,+\infty)[/tex]

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