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A barge travels twice as fast when it is empty as when it is full. If it travels 20 miles north
with a cargo, spends 20 minutes unloading, and returns to its original port
empty, taking 8 hours to complete the entire trip, what is the speed of the barge when it
is empty?



Answer :

V1=(empty)=2*v2(full)
20+20 (go+return)
t1+t2=8hour-20’(1/3 hour)=23/3hour
t1=23/3-t2
v1*t1+v2*t2=20+20
2v2*(23/3-t2)+v2*t2=40
2v2*23/3-2v2*t2+v2t2=40
2v2*23/3-v2t2=40
2v2*23/3-20=40
2v2*23/3=60
v2=60/46/3=180/46=90/23
v1=2*90/23=180/23

Answer:wada

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