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Ina shoots a large marble (Marble A, mass: 0.08 kg) at a smaller marble (Marble B, mass: 0.05 kg) that is sitting still. Marble A was initially moving at a velocity of 0.5 m/s, but after the collision it has a velocity of –0.1 m/s. What is the resulting velocity of marble B after the collision?



Answer :

Answer:

The resulting velocity of marble B after the collision is 0.96 m/s.

Explanation:

Mass of marble A ,[tex]m_1= 0.08 kg[/tex]

Initial velocity of the marble A,[tex]u_1 = 0.5 m/s[/tex]

Mass of marble B,[tex]m_2 = 0.05 kg[/tex]

Initial velocity of the marble B,[tex]u_2 = 0 m/s[/tex]

final velocity of the marble A,[tex]v_1 = -0.1 m/s[/tex]

final velocity of the marble B,[tex]v_2 = ?[/tex]

Applying law of conservation of mass:

[tex]m_1u_1+m_2u_2=m_1v_1+m_2v_2[/tex]

[tex]0.08 kg\times 0.5 m/s+0.05kg\times 0 m/s=0.08 kg\times (-0.1 m/s)+0.05kg \times v_2[/tex]

[tex] v_2=0.96 /s[/tex]

The resulting velocity of marble B after the collision is 0.96 m/s.

Answer:

the other ball will move with speed 0.96 m/s

Explanation:

Here in collision type of questions we can use momentum conservation because there is no force on the system

So here we will have

[tex]m_a v_{1i} + m_b v_{2i} = m_a v_{1f} + m_b v_{2f}[/tex]

so here we have

[tex]0.08(0.5) + 0.05(0) = 0.08(-0.1) + 0.05 v[/tex]

[tex]0.048 = 0.05 v[/tex]

[tex]v = 0.96 m/s[/tex]

So the light ball will move with speed 0.96 m/s