Answer :
if 85 blinks = 15 minutes
then 51 blinks = x (cross multiply)
85 × x = 51 × 15
85x / 85 = (51 x 15) / 85
x = (51 × 3) / 17
x = 3 × 3
x = 9
so he blinked 51 times in 9 minutes
if 1 minute = 60 seconds
then 9 minutes = x (cross multiple)
1 × x = 9 × 60
x = 540
therefore 540 seconds passed when he blinked 51 times
then 51 blinks = x (cross multiply)
85 × x = 51 × 15
85x / 85 = (51 x 15) / 85
x = (51 × 3) / 17
x = 3 × 3
x = 9
so he blinked 51 times in 9 minutes
if 1 minute = 60 seconds
then 9 minutes = x (cross multiple)
1 × x = 9 × 60
x = 540
therefore 540 seconds passed when he blinked 51 times
Solution: The george blink 51 times in 540 seconds.
Explanation:
It is given that Geoge blinks 85 times in 15 minutes and we know that 1 minutes = 60 seconds.
[tex]85 times=15 minutes[/tex]
[tex]85 times=(15 \times 60)seconds[/tex]
[tex]1 times=\frac{900}{85}seconds[/tex]
[tex]1 times=\frac{180}{17}seconds[/tex]
[tex]51times=\frac{180}{17}\times(51)seconds[/tex]
[tex]51times=180\times 3seconds[/tex]
[tex]51times=540seconds[/tex]
Therefore, the george blink 51 times in 540 seconds.
