Answer :
Let [tex]j[/tex] be the number of pages Janet has to read.
so Hallie has [tex]10j[/tex] pages to read.
Altogether, they must read [tex]10j + j[/tex] pages, which is [tex]11j[/tex]. So this means that [tex]11j[/tex] must be equal to [tex]264[/tex].
If you divide both bits by [tex]11[/tex], you get [tex]j = \frac{264}{11} = 24[/tex].
So, Janet has to read [tex]j[/tex] pages, which is [tex]24[/tex], and Hallie has to read [tex]10j[/tex] pages, which is [tex]240[/tex].
so Hallie has [tex]10j[/tex] pages to read.
Altogether, they must read [tex]10j + j[/tex] pages, which is [tex]11j[/tex]. So this means that [tex]11j[/tex] must be equal to [tex]264[/tex].
If you divide both bits by [tex]11[/tex], you get [tex]j = \frac{264}{11} = 24[/tex].
So, Janet has to read [tex]j[/tex] pages, which is [tex]24[/tex], and Hallie has to read [tex]10j[/tex] pages, which is [tex]240[/tex].
they read all together you divide then the quotient you divide it by 10 that's how u get ur answer13.2
