Answer :
[tex]10\frac{3}{4}\to \frac{43}{4} \\\\ 7\frac{1}{4}\to\frac{29}{4} \\\\\\ 10\frac{3}{4}-7\frac{1}{4}=\\\\= \frac{43}{4}-\frac{29}{4}= \\\\ = \frac{14}{4}= \\\\ =\boxed{\frac{7}{2}}[/tex]
There are several ways to do this but the way I'm going to do it is as follows
Change the fractions into improper fractions
Multiply the denominator by the whole number then add the numerator
[tex]10 \frac{3}{4} [/tex]⇒[tex] \frac{43}{4} [/tex]
[tex]7 \frac{1}{4} [/tex]⇒[tex] \frac{29}{4} [/tex]
You subtract the numerators
[tex] \frac{43}{4} [/tex][tex]- \frac{29}{4} [/tex]=[tex] \frac{14}{4} [/tex]
You then divide the numerator(top) by the denominator(bottom)
14÷4=[tex]3 \frac{2}{4} [/tex]⇒[tex] 3\frac{1}{2} [/tex]
Change the fractions into improper fractions
Multiply the denominator by the whole number then add the numerator
[tex]10 \frac{3}{4} [/tex]⇒[tex] \frac{43}{4} [/tex]
[tex]7 \frac{1}{4} [/tex]⇒[tex] \frac{29}{4} [/tex]
You subtract the numerators
[tex] \frac{43}{4} [/tex][tex]- \frac{29}{4} [/tex]=[tex] \frac{14}{4} [/tex]
You then divide the numerator(top) by the denominator(bottom)
14÷4=[tex]3 \frac{2}{4} [/tex]⇒[tex] 3\frac{1}{2} [/tex]