Answer :
bx must be the sum of the numbers in the bracket and c must be the product. So we need to choose 2 numbers that multiply to make 3 and add to make -4.
A negative x negative = positive so
-3*-1=3
-3-1=-4
Therefore:
(x-3)(x-1)
A negative x negative = positive so
-3*-1=3
-3-1=-4
Therefore:
(x-3)(x-1)
[tex]x^2 - 4x + 3=\\
x^2-x-3x+3=\\
x(x-1)-3(x-1)=\\
(x-3)(x-1)[/tex]
