Answer: 5.047m/s
Explanation:
Initial velocity (U) = ?
Height (s) = 1.3m
Time taken (t) =?
g = acceleration due to gravity = 9.8m/s²
From equation of motion;
S = ut - ½gt².........equation (i) (note the negative sign is because the Hooper is moving against gravity).
Velocity at maximum height = 0
V = u - gt ........ equation (ii)
0 = u - gt
t = u/g
Put t = u/g into equation (i)
S = u(u/g) - ½g(u/g)²
S = u²/g - ½u²/g
S = ½u²/g
2S = u²/g
U² = 2Sg
U² = 2 * 1.3 * 9.8
U² = 25.48
U = 5.047m/s (take square root of U²)
