sheemalima
Answered

A dance floor is made from square wooden tiles with a side length of 1
foot. The floor can be laid out as a square or as a rectangle. Yeasmin chooses a rectangular dance floor for her party. The width of the rectangular dance floor is 10 feet less than the width of the square dance floor, and its length is 15 feet greater than the length of the square floor.
How much greater is the length of the rectangular dance floor than its width?
The perimeter of the rectangular dance floor is 130 feet. What are the and width of the dance floor?
If the unit rate is $0.50 per tile , how much would it cost Yeasmin to buy the number of tiles needed to make up the dance floor?



Answer :

chipperrider
Let x be the original width of the square dance floor.

In the rectangle:
Length = x + 15
Width = x - 10
Therefore, the difference between length and width = 25.

Perimeter = 2length + 2width
130=2(x + 15) + 2(x - 10)
130=2x + 30 + 2x -20
130 = 4x + 10
130 - 10 = 4x
x = 120/4
x = 30
Length = x + 15 = 30 + 15 = 45
Width = x - 10 = 30 - 10 = 20
Therefore, the length of the dance floor is 45 feet and the width is 20 feet

The number of tiles is the area of the dance floor because each tile is 1 foot by 1 foot.
Area = length * width
Area = 45 * 20
Area = 900 feet²
Thus, she needs 900 tiles. Each tiles costs $0.50 so,
Total cost = 900 tiles * $ 0.50 = $450.00