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The sum of the digits of a two-digit number is 11. The tens digit is one less
than three times the ones digit. Find the original number.



Answer :

luana
[tex]x+y=11\\ x+1=3y\ \ \ \ --->\ \ \ \ x=3y-1\\\\ 3y-1+y=11\\ 4y-1=11\ \ \ | add\ 1\\ 4y=12\ \ \ | divide\ by\ 4\\ y=3\\\\ x=8\\\\ Original\ number \ is\ 83.[/tex]

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