p = 2.00 atm = 2026.50hPa
T = 27°C = 300K
m = 14.0g |
Mr = 28g/mol | n = m/M = 14g/28g/mol = 0,5mol
R = 83.1 [hPa*L]/[mol*K]
pV = nRT
nRT 0,5mol * 83.1[hPa*L]/[mol*K] * 300K
V = ---------- = ----------------------------------------------------------- = 6.15L
p 2026.5hPa
Answer B.