Answer :

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[tex]C_{m}=\frac{n}{V_{r}}\\\\ m=\frac{m}{M}\\\\ C_{m}=\frac{m}{MV_{r}} \ \ \ \ \Rightarrow \ \ \ \ m=C_{m}MV_{r}}\\\\ C_{m}=0.25\frac{mol}{L}\\ M_{CaBr_{2}}=200\frac{g}{mol}\\ V_{r}=50mL=0.05L\\\\ m=0.25\frac{mol}{L}*200\frac{g}{mol}*0.05L= \emph{\textbf{2.5g}}[/tex]

The mass of the compound can be calculated by the molarity. The mass of the calcium bromide in the given solution is 2.5 g.

The mass of the given compound can be calculated by the molarity formula,

[tex]\bold {M = \dfrac {w}{m\times v} \times 1000}\\\\\bold {w = \dfrac {M\times m\times v}{ 1000}}[/tex]

Where,

M- molarity of the solution =  0.25 M

w - given mass =?

m -molar mass of Calcium bromide =  200 g/mol

v- volume in mL= 50 mL

Put the values in the formula,

[tex]\bold {w = \dfrac {0.25\times 200\times 50}{ 1000}}\\\\\bold {w = 2.5\ g}[/tex]

Therefore, the mass of the calcium bromide in the given solution is 2.5 g.

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