Answer :
5(x+(x+1)+(x+2))=150
5(3x+3)=150
15x+15=150
15x=135
x=9
Your three consecutive integers are 9, 10, and 11.
Let x=1st integer
x+1=2nd integer
x+2=3rd integer
5(x+x+1+x+2)=150
5(3x+3)=150
15x+15=150
15x=135
x=9
So you put what x is
1st integer (x)= 9
Since it's three consecutive integers, you add one to the 2nd integer
2nd integer (x+1)= 10
Then you do the same thing for the third integer
3rd integer (x+2)= 11
x+1=2nd integer
x+2=3rd integer
5(x+x+1+x+2)=150
5(3x+3)=150
15x+15=150
15x=135
x=9
So you put what x is
1st integer (x)= 9
Since it's three consecutive integers, you add one to the 2nd integer
2nd integer (x+1)= 10
Then you do the same thing for the third integer
3rd integer (x+2)= 11
