Answer :
ur asking a bunch of these kind of rate problems xD
[tex]6 ( \frac{1}{15} + \frac{1}{x} )=1[/tex]
In 6 hrs, the welder who does 1/15 of the job in 1 hr and the welder who does 1/x in 1 hr, complete the job (6 hrs.)
[tex] \frac{1}{15} + \frac{1}{x} = \frac{1}{6} [/tex]
Multiply 30 on both sides to cancel out the fractions and we get:
[tex]2 + \frac{30}{x} =5[/tex]
Solving for x:
30/x=3
3x=30
x=10
The second welder would take 10 hours.
[tex]6 ( \frac{1}{15} + \frac{1}{x} )=1[/tex]
In 6 hrs, the welder who does 1/15 of the job in 1 hr and the welder who does 1/x in 1 hr, complete the job (6 hrs.)
[tex] \frac{1}{15} + \frac{1}{x} = \frac{1}{6} [/tex]
Multiply 30 on both sides to cancel out the fractions and we get:
[tex]2 + \frac{30}{x} =5[/tex]
Solving for x:
30/x=3
3x=30
x=10
The second welder would take 10 hours.
