Two welders working together can complete a job in 6 h. One of the welders, working alone, can complete the task in 15 h. How long would it take the second welder, working alone, to complete the task?
ur asking a bunch of these kind of rate problems xD [tex]6 ( \frac{1}{15} + \frac{1}{x} )=1[/tex] In 6 hrs, the welder who does 1/15 of the job in 1 hr and the welder who does 1/x in 1 hr, complete the job (6 hrs.) [tex] \frac{1}{15} + \frac{1}{x} = \frac{1}{6} [/tex] Multiply 30 on both sides to cancel out the fractions and we get: [tex]2 + \frac{30}{x} =5[/tex] Solving for x: 30/x=3 3x=30 x=10 The second welder would take 10 hours.
