Answer :
[tex] \left \{ {{9x-3y=3} \atop {3x+8y=-17\ \ |*(-3)}} \right. \\\\ \left \{ {{9x-3y=3} \atop {-9x-24y=51}} \right. \\+----\\addition\ method\\\\
-27y=54\ \ \ | divide\ by\ -27\\
y=-\frac{54}{27}\\
x=\frac{-17-8y}{3}=\frac{-17-8*(-\frac{54}{27})}{3}=-\frac{1}{3}[/tex]
