Answer :
[tex] n^{2} -7n+12[/tex]
The best way to improve your skill factoring this trinomials is just to practice and practice again.
So basically we need 2 numbers that multiply to 12 and that add up to -7. Using some intuition and some guess and check, we learn that the 2 numbers are -4 and -3. Putting them into 2 binomials, we get
[tex](n-4)(n-3)[/tex]
(n-4)(n-3)
Hope this helps. If you found this helpful, please consider making this the brainliest answer because I just need one more best answer to be virtuoso. Thanks!
The best way to improve your skill factoring this trinomials is just to practice and practice again.
So basically we need 2 numbers that multiply to 12 and that add up to -7. Using some intuition and some guess and check, we learn that the 2 numbers are -4 and -3. Putting them into 2 binomials, we get
[tex](n-4)(n-3)[/tex]
(n-4)(n-3)
Hope this helps. If you found this helpful, please consider making this the brainliest answer because I just need one more best answer to be virtuoso. Thanks!
[tex]n^2-7n+12=0 \\ \\ (n-4)(n-3)=0 [/tex]
if it equal 0
[tex]n^2-7n+12=0 \\ \\ (n-4)(n-3)=0 \\ n-4=0 \\ n=4 \\ \\ n-3=0 \\ n=3 \\ \\ x_1=4,x_2=3 [/tex]
if it equal 0
[tex]n^2-7n+12=0 \\ \\ (n-4)(n-3)=0 \\ n-4=0 \\ n=4 \\ \\ n-3=0 \\ n=3 \\ \\ x_1=4,x_2=3 [/tex]
