Answer :
[tex]0.\overline{9}\\
5.92\overline{1}\\
2.\overline{01}\\
13.14\overline{64}\\
26.\overline{993}\\
30.6\overline{841}\\\\
\frac{3}{8}=\frac{375}{1000}=0.375\\
\frac{4}{5}=\frac{8}{10}=0.8[/tex]
So,
(v) = vinculum or "bar"
1. 0.9999... = .9(v)
2. 5.921(v) over the 1
3. 2.01(v) over the 01
4. 13.146(v) over the 46
5. 26.993(v) over the 993
6. 30.6841(v) over the 841
Part B
1. 3/8 = 0.375 (not repeating)
2. 4/5 = 0.80 (not repeating)
(v) = vinculum or "bar"
1. 0.9999... = .9(v)
2. 5.921(v) over the 1
3. 2.01(v) over the 01
4. 13.146(v) over the 46
5. 26.993(v) over the 993
6. 30.6841(v) over the 841
Part B
1. 3/8 = 0.375 (not repeating)
2. 4/5 = 0.80 (not repeating)