30-11-2014
Mathematics

Answered

when factored completely, what are the factors of 4x^2-16 ?

Answer :

konrad509 konrad509

30-11-2014

[tex]4x^2-16=\\ 4(x^2-4)=\\ 4(x-2)(x+2)[/tex]

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Аноним Аноним

02-12-2014

[tex]Use:a^2-b^2=(a-b)(a+b)\\\\4x^2-16=4(x^2-4)=4(x^2-2^2)=\boxed{4(x-2)(x+2)}[/tex]

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