Anonym Anonym
  • 30-11-2014
  • Mathematics
Answered

when factored completely, what are the factors of 4x^2-16 ?



Answer :

konrad509
konrad509 konrad509
  • 30-11-2014
[tex]4x^2-16=\\ 4(x^2-4)=\\ 4(x-2)(x+2)[/tex]
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Аноним Аноним
  • 02-12-2014
[tex]Use:a^2-b^2=(a-b)(a+b)\\\\4x^2-16=4(x^2-4)=4(x^2-2^2)=\boxed{4(x-2)(x+2)}[/tex]
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