Answered

A liquid with a specific heat of 1,900 J/kg·°C has 4,750 joules of heat energy is added to it. If the
temperature increases from 20°C to 30°C, what is the mass of the liquid?



Answer :

Q=mcΔT

Q=heat energy = 4750J
m=mass = ?
c= specific heat capacity = 1900J/(K·kg)
ΔT=change in heat = 30-20=10

[tex]m= \frac{Q}{c(dT)}[/tex] = 0.025kg=25g

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