Answer :
[tex]K=\frac{wv^2}{2g}\ \ \ \ \ |multiply\ both\ sides\ by\ 2g\\\\2gK=wv^2\ \ \ \ \ |divide\ both\ sides\ by\ v^2\\\\\boxed{w=\frac{2gK}{v^2}}[/tex]
[tex]K=\frac{wv^2}{2g}\ \ \ \ \ \ |\cdot2g\\\\2Kg=wv^2\ \ \ \ \ |:v^2\\\\\boxed{w=\frac{2Kg}{v^2}}[/tex]
