Answer :
[tex](2x-3)^2=18\\
2x-3=\sqrt{18} \vee 2x-3=-\sqrt{18}\\
2x=3+3\sqrt{2} \vee 2x=3-3\sqrt{2}\\
x=\frac{3+3\sqrt{2}}{2} \vee x=\frac{3-3\sqrt{2}}{2}\\
[/tex]
[tex](2x-3)^2=18\ \ \ \ | make\ \sqrt{}\\\\
|2x-3|=\sqrt{18}\\\\
2x-3=\sqrt{18}\ \ \ or\ \ \ -2x+3=\sqrt{18}\\\\
2x=\sqrt{18}+3\ \ \ \ or\ \ \ \ -2x=\sqrt{18}-3\\\\
x=\frac{\sqrt{9*2}+3}{2}\ \ \ or\ \ \ \ x=\frac{\sqrt{9*2}-3}{-2}\\\\
x=\frac{3\sqrt{2}+3}{2}\ \ \ or\ \ \ \ x=\frac{-3\sqrt{2}+3}{2}[/tex]