Answer :

luana
[tex]3(n-4)\leq-12+2n\ \ \ | omit\ the\ bracket\\\\ 3n-12\leq-12+2n\ \ \ | add\12\\\\ 3n\leq2n\ \ \ | subtract\ 2n\\\\ n\leq0\\\\ Solution\ is\ n\in(-\infty,0][/tex]