Answer :
The slope of the first equation would be -5/2 because
2y=-5x+8
y=-5x/2+4
The y intercept of the 2nd equation is when x=0, so -7y=10
y=-10/7
The equation of the line would be y=-5x/2-10/7
Or in standard form....
5x/2+y=-10/7
5x+27=-20/7
2y=-5x+8
y=-5x/2+4
The y intercept of the 2nd equation is when x=0, so -7y=10
y=-10/7
The equation of the line would be y=-5x/2-10/7
Or in standard form....
5x/2+y=-10/7
5x+27=-20/7
[tex]5x+2y=8\ \ \Rightarrow\ \ 2y=-5x+8\ \ \Rightarrow\ \l_1:\ y=- \frac{5}{2}x+8\\ \\ l_2:\ y=ax+b\ \ \ and\ \ \ l_2\ ||\ l_1\ \ \ \Leftrightarrow\ \ \ a=- \frac{5}{2} \\ \\l_2:\ y=- \frac{5}{2}x+b\\ \\3x-7y=10\ \ \ and\ \ \ x=0 \ \ \ \Rightarrow\ \ \ 3\cdot0-7y=10 \ \ \Rightarrow\ \ \ y=- \frac{10}{7} \\ \\b=- \frac{10}{7}\ \ \ \Rightarrow\ \ \ l_2:\ y=- \frac{5}{2}x- \frac{10}{7}\\ \\ l_2:\ \frac{5}{2}x+y=- \frac{10}{7}\ \ /\cdot14\\ \\l_2:\ 35x+7y=-20 [/tex]
