[tex]8-2b=-\dfrac{2}{3}(12b+6)\\ 8-2b=-8b-4\\ 6b=-12\\ b=-2\\\\ -5=\dfrac{8m+12}{4}\\ -5=2m+3\\ 2m=-8\\ m=-4\\\\ -12j+4=-4-12j\\ 4=-4\\ j\in\emptyset \Rightarrow A [/tex]
[tex]5x+7=\dfrac{1}{2}(10x+12)\\
5x+7=5x+6\\
7=6\\
x\in \emptyset \Rightarrow B\\\\
-\dfrac{1}{9}(18x+27)=1+x-4-3x\\
-2x-3=-2x-3\\
0=0\\
x\in\mathbb{R} \Rightarrow C\\\\
\dfrac{x+3}{4}=\dfrac{3}{4}x+\dfrac{3}{4}|\cdot4\\
x+3=3x+3\\
-2x=0\\
x=0 \Rightarrow A\\\\
4+3x=2x-10\\
x=-14 \Rightarrow A
[/tex]
