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A line passes through the point (–6, –2), and its y-intercept is (0, 1). What is the equation of the line that is perpendicular to this line and passes through the point (2, 3)?



Answer :

crisforp
The slope of first line is m 1= ( 1 - 0 ) / ( - 2 - ( - 6 ) );
m = 1 / 4 ;
Because the second line is perpendicular to the first line, m2 * m1 = - 1 ;
m2 * ( 1 / 4 ) = -1;
 m2 = - 4 ;
The equation of the second line is : y - 3 = ( - 4 )( x - 2 );
y - 3 = -4x + 8 ;
y = -4x + 11.
sweetttweety1

Answer:

Step-by-step(- 6 1?

Write an equation in slope-intercept form of the line through point (6, -1) with slope m = 4. Summary: The equation of the line passing through point (6, -1) with slope m = 4, in slope-intercept form is y = 4x - 25. explanation:

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