Answer :
This is a problem of proportions. The initial data gives you the ratios, then you can use them to build proportions for each case. A. Siena's game to souvenier ratio is 8/12 then you can build the proportion: 8/12 = 26/x and solve for x: x = 26*12/8 = 17.33 B. Ren's souvenier to snacks ratio is 20 / 10, the the proportion is 20 / 10 = 5 / x => x = 5 * 10 / 20 = 2.5
Let
x-------> money spent in snacks
y-------> money spent in games
z-------> money spent in souvenirs
we know that
Siena's ratios
[tex] \frac{x}{y} =\frac{5}{8} \\\\ \frac{x}{z}= \frac{5}{12} \\ \\ \frac{y}{z} =\frac{8}{12} [/tex]
Ren's ratios
[tex] \frac{x}{y} =\frac{10}{8} \\\\ \frac{x}{z}= \frac{10}{20} \\ \\ \frac{y}{z} =\frac{8}{20} [/tex]
Part A) A. Siena wants to spend money using the same ratios as on her last trip to the carnival. If she spends $[tex] 26 [/tex] on games, how much will she spend on souvenirs?
So
[tex] \frac{y}{z} =\frac{8}{12} \\ \\ 12y=8z\\ \\ z=\frac{12}{8} y [/tex]
[tex] y=26 [/tex]-----> money spent in games
substitute the value of y
[tex] z=\frac{12}{8} y\\ \\ z=\frac{12}{8} *26\\ \\ z=39 [/tex]
therefore
the answer Part A) is
Siena spend on souvenirs $[tex] 39 [/tex]
Part B) Ren wants to spend money using the same ratios as on his last trip to the carnival. If he spends $[tex] 5 [/tex] on souvenirs, how much will he spend on snacks?
[tex] \frac{x}{z} =\frac{10}{20} \\ \\ 20x=10z\\ \\ x=\frac{1}{2} *z [/tex]
[tex] z=5 [/tex] ----> money spent in souvenirs
Substitute the value of z
[tex] x=\frac{1}{2} *z\\ \\ x=\frac{1}{2} *5\\ \\ x=2.5 [/tex]
therefore
the answer part B) is
Ren spend on snacks $[tex] 2.5 [/tex]