Answer :
Let the first even integer be x.
The second even integer is x+2.
The third even integer is x+4.
[tex]x+x+2+x+4=42 \\ 3x+6=42 \\ 3x=36 \\ x=12 \\ \\ x+2=12+2=14 \\ x+4=12+4=16[/tex]
The three integers are 12, 14 and 16.
The second even integer is x+2.
The third even integer is x+4.
[tex]x+x+2+x+4=42 \\ 3x+6=42 \\ 3x=36 \\ x=12 \\ \\ x+2=12+2=14 \\ x+4=12+4=16[/tex]
The three integers are 12, 14 and 16.