Answer :
Solve by applying PEMDAS - the order of operations:
P = Parenthesis or brackets
E = Exponents or radicals whichever comes first
M = Multiplication or division whichever comes first
D = Division or multiplication whichever comes first
A = Addition or subtraction whichever comes first
S = Subtraction or addition whichever comes first
.
4{[5(x-3)+2]-3[2(2x+5)-9]
4{[5x-15+2]-3[4x+10-9]}
4{[5x-13]-3[4x+1]}
4{[5x-13]-(12x+3)}
4{[5x-13]-12x+3}
4{5x-13-12x+3}
4{-7x-10}
-28x-40
P = Parenthesis or brackets
E = Exponents or radicals whichever comes first
M = Multiplication or division whichever comes first
D = Division or multiplication whichever comes first
A = Addition or subtraction whichever comes first
S = Subtraction or addition whichever comes first
.
4{[5(x-3)+2]-3[2(2x+5)-9]
4{[5x-15+2]-3[4x+10-9]}
4{[5x-13]-3[4x+1]}
4{[5x-13]-(12x+3)}
4{[5x-13]-12x+3}
4{5x-13-12x+3}
4{-7x-10}
-28x-40
pemdas
parenthasees exponents mult/division additon/subtraction
parethenasees
x-3 and x+5 we can't do anything with so next
5(x-3)=5x-15
2(x+5)=2x+10
5x-15+2=5x-13
(2x+10-9)=2x+1
(5x-13)-3(2x+1)
-3(2x+1)=-6x-3
5x-13-6x-3=-x-16
4(-x-16)=-4x-64
the answer is -4x-64
parenthasees exponents mult/division additon/subtraction
parethenasees
x-3 and x+5 we can't do anything with so next
5(x-3)=5x-15
2(x+5)=2x+10
5x-15+2=5x-13
(2x+10-9)=2x+1
(5x-13)-3(2x+1)
-3(2x+1)=-6x-3
5x-13-6x-3=-x-16
4(-x-16)=-4x-64
the answer is -4x-64