Answer :
This is a system of equations. If M=Marie's score and R=Ralph's score then
M=3R-5
and
M+R=215
Using substitution, we get:
(3R-5)+R=215
4R-5=215
4R=220
R=55
Now we know Ralph scored a 55. We then plug this into either equation to get Marie's score:
M+(55)=215
M=160
So Ralph scored a 55 and Marie scored a160
M=3R-5
and
M+R=215
Using substitution, we get:
(3R-5)+R=215
4R-5=215
4R=220
R=55
Now we know Ralph scored a 55. We then plug this into either equation to get Marie's score:
M+(55)=215
M=160
So Ralph scored a 55 and Marie scored a160
This is a system of equations
M=3R-5
215=M+R
you can use substitution
215=3R-5+R
combine like terms, then
simplify and isolate the variable
215=4R-5
add 5 on both sides
220=4R
divide by 4 on both sides
R=55
Plug R into a equation to find M
215=55+M
subtract by 55 on both sides
M=160
M=3R-5
215=M+R
you can use substitution
215=3R-5+R
combine like terms, then
simplify and isolate the variable
215=4R-5
add 5 on both sides
220=4R
divide by 4 on both sides
R=55
Plug R into a equation to find M
215=55+M
subtract by 55 on both sides
M=160